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24m^2-36m-324=0
a = 24; b = -36; c = -324;
Δ = b2-4ac
Δ = -362-4·24·(-324)
Δ = 32400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{32400}=180$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-36)-180}{2*24}=\frac{-144}{48} =-3 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-36)+180}{2*24}=\frac{216}{48} =4+1/2 $
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